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# How to Solve Clocks Question Quickly

## How to Solve Clock Questions Quickly in Aptitude

**The clock’s circumference is divided into 60 equal divisions or parts. These equal divisions are said to be minute spaces or minute divisions. A clock has two hands,the hour hand and the minute hand. The hour hand is smaller and slower than the minute hand.When the minute hand moves forward twelve clock numbers and covers 60 minute spaces. Then, the hour hand moves forward one clock number and covers 5 minute spaces known as one hour.**

**Type 1: How To Solve Quickly Clocks**

**Question 1. Calculate the angle between the two hands of a clock when the time shown by the clock is 7:30 a.m.**

**Options:**

**A. 100 ^{0}**

**B. 155 ^{0}**

**C.200 ^{0}**

**D. None of the above**

**Solution **From the formula

Angle = 11/2M – 30H, where M =30, and H =7

= 11/2*30 – 30 x 7

= |165 – 210|, taking the mode of the values, we get

= 155^{0}

**Correct Answer: Option B**

**Question 2.** **Calculate the degree at which the hour hand moves when the minute’s hand moves 750 times.**

**Options:**

**A. 13 ^{0}**

**B. 12*(3/6)°**

**C. 15(3/6)°**

**D. Cannot be determined**

**Solution: **Degrees covered by hour hand in one minute = 1/60

The minute hand will cover 750/60 degrees in 650 minutes.

This can be written as = 12 (3/6)° degrees.

**Correct Answer: Option B**

**Question 3. What is the angle an hour hand has to trace when it covers the time from 8 A.M in the morning to 2 o’clock in the afternoon?**

**Options**

**A. 120**

**B.180**

**C.250**

**D. None of the above**

**Solution: **Time between 8 A.M to 2 P.M = 6 hours.

Therefore, the angle traced by the hour hand = 360/12 x 6

= 180^{0}

**Correct Answer: Option B**

**Type 2: Solve Quickly Clocks Ques.**

**Ques 1. Determine the time at which the minute and the hour hand will be in the same straight line facing opposite directions between 2 and 3 o’clock.**

**Options:**

**A. 2:43(7/11) P.M.**

**B. 2:45 P.M.**

**C.2:50(1/13) P.M.**

**D. None of the above**

**Solution: **Degrees in a straight line = 180^{0}

When we apply the formula, 11/2M – 30H

= (180+60)/2 = 11M

Or M =43(7/11)

**Correct Answer: Option A**

**Question 2. A clock is set to correct timing at 8 a.m. In the next 24 hours, it gains 10 minutes. What will be the true time when the clock displays time to be 1 P.M?**

**Options**

**A. 12: 48 P.M**

**B. 2:50 P.M.**

**C. 1: 30 A.M.**

**D. Cannot Be Determined**

**Solution: **Number of hours from 8 A.M on a day to 1 P.M the next day = 29

24 hours 10 minutes of this clock = 24 hours of a correct clock

145/6 hours of this incorrect clock = 24 hours of the correct clock

29 hours of incorrect clock = 24 x 6/145 x 29 hours of the correct clock

= 28 hours and 48 minutes of the correct clock

Therefore, the correct time is 28 hours and 48 minutes after 8 A.M

Which means, the true time will be 12:48 P.M.

**Correct Answer: Option A**

**Question 3. What is the time between 4 and 5 o’clock, when the hands of the watch points in the opposite direction?**

**Options**

**A. 4:54 o’clock**

**B. 5 o’clock**

**C. 10 o’clock**

**D. Cannot be Determined**

**Solution: **Hands of the clock are 20 min. spaces apart when the time is 4 o’clock

They must be 30 min. Spaces apart to be in opposite directions.

Minute hand needs to gain 50 min. spaces

A clock gains 55 min. spaces in 60 minutes

50 min spaces are gained in

= 60/55 x 50 minutes

= 54(6/11)

The needed time = 54(6/11) past 4, or

= 4: 54

**Correct Answer: Option A**

**Read Also – Formulas to solve clock problems easily**

**Read Also – Tips and tricks to solve clock Problem**

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